LATSTONE

index · ← LTLAXIO5 · FINANCE3 →
:: Stone Lattices
::  by Adam Grabowski
::
:: Received October 22, 2015
:: Copyright (c) 2015-2026 Association of Mizar Users
::           (Stowarzyszenie Uzytkownikow Mizara, Bialystok, Poland).
:: This code can be distributed under the GNU General Public Licence
:: version 3.0 or later, or the Creative Commons Attribution-ShareAlike
:: License version 3.0 or later, subject to the binding interpretation
:: detailed in file COPYING.interpretation.
:: See COPYING.GPL and COPYING.CC-BY-SA for the full text of these
:: licenses, or see http://www.gnu.org/licenses/gpl.html and
:: http://creativecommons.org/licenses/by-sa/3.0/.

environ

 vocabularies SUBSET_1, LATTICES, LATSTONE, XBOOLE_0, TARSKI, EQREL_1, PBOOLE,
      ORDINAL4, XXREAL_2, STRUCT_0, ZFMISC_1, LATTICE5, FILTER_0, LATTICE4,
      TOPS_1, REWRITE1, MOEBIUS2, NAT_1, FINSET_1, XCMPLX_0, MOEBIUS1, RELAT_1,
      BINOP_1, REALSET1, LATTICEA, XXREAL_0, CARD_1, NUMBERS, NEWTON, ARYTM_3;
 notations TARSKI, ZFMISC_1, XBOOLE_0, RELAT_1, ORDINAL1, NAT_1, FINSET_1,
      ARYTM_3, BINOP_1, REALSET1, SUBSET_1, NAT_D, ENUMSET1, XCMPLX_0,
      XXREAL_0, CARD_1, NUMBERS, NEWTON, INT_2, FUNCT_1, FUNCT_2, STRUCT_0,
      LATTICES, LATTICE3, FILTER_0, FILTER_1, FILTER_2, LATTICE4, MOEBIUS1,
      MOEBIUS2, LATTICEA;
 constructors DOMAIN_1, XBOOLE_0, FILTER_1, NAT_1, ORDINAL1, INT_2, NEWTON,
      ARYTM_3, NAT_D, SQUARE_1, ENUMSET1, ZFMISC_1, FILTER_0, FINSET_1,
      FILTER_2, LATTICE4, MOEBIUS1, XREAL_0, XCMPLX_0, XXREAL_0, BINOP_1,
      REALSET2, LATTICE3, PARTFUN1, MOEBIUS2, SUBSET_1, BOOLEALG, REALSET1,
      LATTICEA;
 registrations STRUCT_0, LATTICES, INT_1, FILTER_1, MOEBIUS1, MOEBIUS2,
      XCMPLX_0, INT_3, NEWTON, NAT_1, ORDINAL1, XXREAL_0, RELSET_1, LATTICE6;
 requirements SUBSET, BOOLE, REAL, NUMERALS;
 definitions TARSKI, XBOOLE_0, LATTICES;
 equalities FILTER_1;
 theorems LATTICES, FILTER_0, FILTER_2, MSUALG_7, MOEBIUS2, MOEBIUS1, NEWTON,
      ENUMSET1, INT_2, NAT_5, TARSKI, BOOLEALG, FILTER_1, ZFMISC_1, XTUPLE_0,
      LATTICEA, LATTICE4;

begin :: Preliminaries

:: The main aim of this article is to provide a formal counterpart
:: for the paper of Jouni J\"arvinen "Lattice theory for rough sets",
:: in Transactions of Rough Sets, VI, LNCS vol. 4374, pp. 400--498, 2007.
:: The corresponding items are marked by the acronym LTRS. We deal
:: with Section 4.3, page 423--426.

theorem ThA:
  for L being distributive Lattice, S being Sublattice of L holds
    S is distributive
  proof
    let L be distributive Lattice, S be Sublattice of L;
    let a,b,c be Element of S;
    reconsider aa = a, bb = b, cc = c as Element of L by FILTER_2:68;
A2: b "\/" c = bb "\/" cc by MSUALG_7:11;
    reconsider ab = aa "/\" bb, ac = aa "/\" cc as Element of L;
A4: ab = a "/\" b & ac = a "/\" c by MSUALG_7:11;
    a "/\" (b "\/" c) = aa "/\" (bb "\/" cc) by MSUALG_7:11,A2
       .= (aa "/\" bb) "\/" (aa "/\" cc) by LATTICES:def 11
       .= (a "/\" b) "\/" (a "/\" c) by MSUALG_7:11,A4;
    hence thesis;
  end;

registration let L be distributive Lattice;
  cluster -> distributive for Sublattice of L;
  coherence by ThA;
end;

registration let L1, L2 be bounded Lattice;
  cluster [:L1,L2:] -> bounded;
  coherence by FILTER_1:41;
end;

 reserve L for Lattice;
 reserve I,P for non empty ClosedSubset of L;

theorem ThB:
  L is lower-bounded & Bottom L in I implies latt (L,I) is lower-bounded
    & Bottom latt (L,I) = Bottom L
  proof
    set b9 = the Element of latt (L,I);
    reconsider b = b9 as Element of L by FILTER_2:68;
    assume
A0: L is lower-bounded & Bottom L in I;
    set c = Bottom L;
    reconsider c9 = c as Element of latt (L,I) by FILTER_2:72,A0;
    ex c9 being Element of latt (L,I) st
    for a9 being Element of latt (L,I) holds c9 "/\" a9 = c9 & a9 "/\" c9 = c9
    proof
    take c9;
    let a9 be Element of latt (L,I);
    reconsider a = a9 as Element of L by FILTER_2:68;
    thus c9 "/\" a9 = c "/\" a by FILTER_2:73 .= c9 by A0;
    hence thesis;
    end;
    hence
W1: latt (L,I) is lower-bounded by LATTICES:def 13;
    for a9 being Element of latt (L,I) holds c9 "/\" a9 = c9 & a9 "/\" c9 = c9
    proof
      let a9 be Element of latt (L,I);
      reconsider a = a9 as Element of L by FILTER_2:68;
      thus c9 "/\" a9 = c "/\" a by FILTER_2:73  .= c9 by A0;
      hence thesis;
    end;
    hence thesis by LATTICES:def 16,W1;
  end;

theorem ThC:
  L is upper-bounded & Top L in I implies latt (L,I) is upper-bounded
    & Top latt (L,I) = Top L
  proof
    set b9 = the Element of latt (L,I);
    reconsider b = b9 as Element of L by FILTER_2:68;
    assume
A0: L is upper-bounded & Top L in I;
    set c = Top L;
    reconsider c9 = c as Element of latt (L,I) by FILTER_2:72,A0;
    ex c9 being Element of latt (L,I) st
    for a9 being Element of latt (L,I) holds c9 "\/" a9 = c9 & a9 "\/" c9 = c9
    proof
    take c9;
    let a9 be Element of latt (L,I);
    reconsider a = a9 as Element of L by FILTER_2:68;
    thus c9 "\/" a9 = c "\/" a by FILTER_2:73 .= c9 by A0;
    hence thesis;
    end;
    hence
W1: latt (L,I) is upper-bounded by LATTICES:def 14;
    for a9 being Element of latt (L,I) holds c9 "\/" a9 = c9 & a9 "\/" c9 = c9
    proof
      let a9 be Element of latt (L,I);
      reconsider a = a9 as Element of L by FILTER_2:68;
      thus c9 "\/" a9 = c "\/" a by FILTER_2:73 .= c9 by A0;
      hence thesis;
    end;
    hence thesis by LATTICES:def 17,W1;
  end;

begin :: Pseudocomplements in Lattices

::$N Pseudocomplement

definition let L be non empty LattStr;
  let a,b be Element of L;
  pred a is_a_pseudocomplement_of b means
    a "/\" b = Bottom L &
    for x being Element of L st b "/\" x = Bottom L holds x [= a;
end;

:: p. 122 6.1 Definition from Gratzer

definition let L be non empty LattStr;
  attr L is pseudocomplemented means :def2:
    for x being Element of L
    ex y being Element of L st y is_a_pseudocomplement_of x;
end;

:: LTRS: Example 43(a)

theorem Th1:
  for L being Boolean Lattice holds L is pseudocomplemented
  proof
    let L be Boolean Lattice;
    L is pseudocomplemented
    proof
      let x be Element of L;
      take y = x`;
      for z being Element of L st x "/\" z = Bottom L holds z [= y
      proof
        let z be Element of L;
        assume E1: x "/\" z = Bottom L;
        z = z "/\" Top L .= z "/\" (x "\/" y) by LATTICES:21
         .= (z "/\" x) "\/" (z "/\" y) by LATTICES:def 11 .= z "/\" y by E1;
        hence z [= y by LATTICES:4;
      end;
      hence thesis by LATTICES:20;
    end;
    hence thesis;
  end;

registration
  cluster Boolean -> pseudocomplemented for Lattice;
  coherence by Th1;
end;

registration
  cluster Boolean pseudocomplemented bounded for Lattice;
  existence
  proof
    set L = the Boolean Lattice;
    take L;
    thus thesis;
  end;
end;

:: Pseudocomplements are unique

theorem Th2:
  for L being pseudocomplemented lower-bounded Lattice,
  a, b, x being Element of L st a is_a_pseudocomplement_of x &
    b is_a_pseudocomplement_of x holds a = b
  proof
    let L be pseudocomplemented lower-bounded Lattice;
    let a, b, x be Element of L;
    assume that
a1: a is_a_pseudocomplement_of x and
b1: b is_a_pseudocomplement_of x;
a2: a "/\" x = Bottom L by a1;
b2: b "/\" x = Bottom L by b1;
ab1:b [= a by a1,b2;
    a [= b by b1,a2;
    hence a = b by ab1,LATTICES:8;
  end;

:: The unique pseudocomplement

definition let L be non empty LattStr, x be Element of L;
  assume A1:L is pseudocomplemented lower-bounded Lattice;
  func x* -> Element of L means :def3:
    it is_a_pseudocomplement_of x;
  existence by def2,A1;
  uniqueness by A1,Th2;
end;

theorem ThD:
  for L being pseudocomplemented lower-bounded Lattice, x being Element of L
  holds x* "/\" x = Bottom L
  proof
    let L be pseudocomplemented lower-bounded Lattice, x be Element of L;
    x* is_a_pseudocomplement_of x by def3;
    hence thesis;
  end;

reserve L for lower-bounded pseudocomplemented Lattice;

:: LTRS: Lemma 42(a)

theorem Th5:
  for a being Element of L holds a [= a**
  proof
    let a be Element of L;
a1: a** is_a_pseudocomplement_of a* by def3;
    a* is_a_pseudocomplement_of a by def3;
    hence thesis by a1;
  end;

:: LTRS: Lemma 42(b)

theorem Th6:
  for a, b being Element of L holds a [= b implies b* [= a*
  proof
    let a, b be Element of L;
    assume a [= b; then
a1: a "/\" b = a by LATTICES:4;
a2: a* is_a_pseudocomplement_of a by def3;
    a "/\" (b*) = (b* "/\" b) "/\" a by a1,LATTICES:def 7
    .= Bottom L "/\" a by ThD .= Bottom L;
    hence b* [= a* by a2;
  end;

:: LTRS: Lemma 42(c)

theorem Th7:
  for a being Element of L holds a* = a***
  proof
    let a be Element of L;
a1: a*** [= a* by Th6,Th5;
    a* [= a*** by Th5;
    hence thesis by a1,LATTICES:8;
  end;

:: LTRS: Example 43(c)
theorem Th11:
  for L being pseudocomplemented bounded Lattice holds (Bottom L)* = Top L
  proof
    let L be pseudocomplemented bounded Lattice;
    Top L is_a_pseudocomplement_of Bottom L by LATTICES:19;
    hence (Bottom L)* = Top L by def3;
  end;

:: LTRS: Example 43(c)
theorem Th11a:
  for L being pseudocomplemented bounded Lattice holds (Top L)* = Bottom L
  proof
    let L be pseudocomplemented bounded Lattice;
    for x be Element of L st Top L "/\" x = Bottom L holds x [= Bottom L; then
    Bottom L is_a_pseudocomplement_of Top L;
    hence (Top L)* = Bottom L by def3;
  end;

:: Pseudocomplements are precisely complements in complemented lattices.
:: A complement (if exists) is always a pseudocomplement.

:: LTRS: Example 43(a)
theorem ThE:
  for L being Boolean Lattice, x being Element of L holds x` = x*
  proof
    let L be Boolean Lattice, x be Element of L;
a1: x* [= x`
    proof
      x* "/\" x = Bottom L by ThD;
      hence thesis by LATTICES:25;
    end;
    x` [= x*
    proof
a1:   (x`) "/\" x = Bottom L by LATTICES:20;
      x* is_a_pseudocomplement_of x by def3;
      hence thesis by a1;
    end;
    hence thesis by a1,LATTICES:8;
  end;

:: Connection between pseudocomplements and the functor from LATTICEA

theorem ThF:
  for L being pseudocomplemented bounded Lattice, x, y being Element of L st
    y is_a_pseudocomplement_of x holds y in PseudoComplements x
  proof
    let L be pseudocomplemented bounded Lattice, x, y be Element of L;
    assume y is_a_pseudocomplement_of x; then
    x "/\" y = Bottom L; then
    y in { xx where xx is Element of L : x "/\" xx = Bottom L };
    hence thesis by LATTICEA:def 8;
  end;

theorem
  for L being pseudocomplemented bounded Lattice, x being Element of L holds
    x* in PseudoComplements x
  proof
    let L be pseudocomplemented bounded Lattice, a be Element of L;
    a* is_a_pseudocomplement_of a by def3;
    hence thesis by ThF;
  end;

begin :: Skeleton of a Pseudocomplemented Lattice

definition let L be lower-bounded pseudocomplemented Lattice;
  func Skeleton L -> Subset of L equals
    the set of all a* where a is Element of L;
  coherence
  proof
    { a* where a is Element of L : not contradiction }
      c= the carrier of L
    proof
      let x be object;
      assume x in { a* where a is Element of L : not contradiction };
      then consider a being Element of L such that
A1:   x = a*;
      thus thesis by A1;
    end;
    hence thesis;
  end;
end;

theorem
  for L being lower-bounded pseudocomplemented Lattice holds
    Skeleton L = { a where a is Element of L : a** = a }
  proof
    let L be lower-bounded pseudocomplemented Lattice;
    thus Skeleton L c= { a where a is Element of L : a** = a }
    proof
      let x be object;
      assume x in Skeleton L; then
      consider a being Element of L such that
a1:   x = a*;
      a*** = a* by Th7;
      hence thesis by a1;
    end;
    let x be object;
    assume x in { a where a is Element of L : a** = a };
    then consider a being Element of L such that
a3: x = a & a** = a;
    thus thesis by a3;
  end;

:: LTRS: Lemma 44(a), p. 424

theorem Th13:
  for L being lower-bounded pseudocomplemented Lattice, x being Element of L
  holds x in Skeleton L iff x** = x
  proof
    let L be lower-bounded pseudocomplemented Lattice, x be Element of L;
    hereby
      assume x in Skeleton L; then
      consider a being Element of L such that
a1:   x = a*;
      thus x** = x by a1,Th7;
    end;
    assume x** = x;
    hence x in Skeleton L;
  end;

registration let L be bounded pseudocomplemented Lattice;
  cluster Skeleton L -> non empty;
  coherence
  proof
    set x = the Element of L;
    x* in Skeleton L;
    hence thesis;
  end;
end;

theorem
  for L being pseudocomplemented distributive lower-bounded Lattice holds
  for a, b being Element of L st a in Skeleton L & b in Skeleton L holds
  a "/\" b in Skeleton L
  proof
    let L be pseudocomplemented distributive lower-bounded Lattice;
    let a, b be Element of L;
    assume a in Skeleton L & b in Skeleton L; then
A2: a = a** & b = b** by Th13;
    a* [= (a "/\" b)* by Th6,LATTICES:6; then
B2: (a "/\" b)** [= a by A2,Th6;
    b* [= (a "/\" b)* by Th6,LATTICES:6; then
    (a "/\" b)** [= b** by Th6; then
B1: (a "/\" b)** [= a "/\" b by B2,FILTER_0:7,A2;
    a "/\" b [= (a "/\" b)** by Th5; then
    a "/\" b = (a "/\" b)** by B1,LATTICES:8;
    hence thesis;
  end;

begin :: Stone Identity

definition let L be non empty LattStr;
  attr L is satisfying_Stone_identity means :SatStone:
    for x being Element of L holds x* "\/" (x**) = Top L;
end;

theorem Th4:
  for L being Boolean Lattice holds L is satisfying_Stone_identity
  proof
    let L be Boolean Lattice, x be Element of L;
    x* "\/" ((x*)*) = Top L
    proof
      x* "\/" ((x*)*) = x` "\/" ((x*)*) by ThE .= x` "\/" ((x`)*) by ThE
      .= x` "\/" ((x`)`) by ThE .= Top L by LATTICES:21;
      hence thesis;
    end;
    hence thesis;
  end;

registration
  cluster Boolean -> satisfying_Stone_identity for Lattice;
  coherence by Th4;
end;

registration
  cluster satisfying_Stone_identity pseudocomplemented Boolean for Lattice;
  existence
  proof
    set L = the Boolean Lattice;
    take L;
    thus thesis;
  end;
end;

:: LTRS: Lemma 44(b), p. 424

theorem Th12:
  for L being pseudocomplemented distributive bounded Lattice holds
    L is satisfying_Stone_identity iff for a, b being Element of L holds
      (a "/\" b)* = (a*) "\/" (b*)
  proof
    let L be pseudocomplemented distributive bounded Lattice;
    hereby
      assume
 a11: L is satisfying_Stone_identity;
      let a, b be Element of L;
      set g = a "/\" b;
a0:   g "/\" (a* "\/" (b*))
        = ((a*) "/\" g) "\/" (g "/\" (b*)) by LATTICES:def 11
       .= (((a*) "/\" a) "/\" b) "\/" (g "/\" (b*))
         by LATTICES:def 7
       .= (((a*) "/\" a) "/\" b) "\/" (a "/\" (b "/\" (b*)))
         by LATTICES:def 7
       .= ((Bottom L) "/\" b) "\/" (a "/\" (b "/\" (b*))) by ThD
       .= ((Bottom L) "/\" b) "\/" (a "/\" Bottom L) by ThD .= Bottom L;
      for x be Element of L st g "/\" x = Bottom L holds x [= a* "\/" (b*)
      proof
        let x be Element of L;
        set z = b "/\" x;
        set w = x "/\" (a**);
        assume a1: g "/\" x = Bottom L;
a0:     Bottom L [= b "/\" x "/\" (a**) by LATTICES:16;
a2:     (b "/\" x) "/\" a = Bottom L by a1,LATTICES:def 7;
        a* is_a_pseudocomplement_of a by def3; then
        b "/\" x "/\" (a**) [= a* "/\" (a**) by LATTICES:9,a2;
        then b "/\" x "/\" (a**) [= Bottom L by ThD; then
        b "/\" x "/\" (a**) = Bottom L by LATTICES:8,a0; then
a4:     x "/\" (a**) "/\" b = Bottom L by LATTICES:def 7;
        b* is_a_pseudocomplement_of b by def3; then
a5:     x "/\" (a**) [= b* by a4;
a6:     x "/\" (a*) [= a* by LATTICES:6;
        x = x "/\" Top L .= x "/\" ((a*) "\/" (a**)) by a11
        .= (x "/\" (a*)) "\/" (x "/\" (a**)) by LATTICES:def 11;
        hence x [= a* "\/" (b*) by a5,a6,FILTER_0:4;
      end; then
      (a*) "\/" (b*) is_a_pseudocomplement_of (a "/\" b) by a0;
      hence (a "/\" b)* = (a*) "\/" (b*) by def3;
    end;
    assume
a1: for a, b being Element of L holds (a "/\" b)* = (a*) "\/" (b*);
    let x be Element of L;
    x "/\" (x*) = Bottom L by ThD; then
    x* "\/" (x**) = (Bottom L)* by a1;
    hence thesis by Th11;
  end;

::$N Stone algebra

definition
  let L be Lattice;
  attr L is Stone means
    L is pseudocomplemented distributive bounded satisfying_Stone_identity;
end;

registration
  cluster Stone ->
    pseudocomplemented distributive bounded satisfying_Stone_identity
      for Lattice;
  coherence;
  cluster pseudocomplemented distributive bounded satisfying_Stone_identity
      -> Stone for Lattice;
  coherence;
end;

:: LTRS:

theorem
  for L being pseudocomplemented distributive bounded Lattice holds
    L is satisfying_Stone_identity iff for a, b being Element of L st
    a in Skeleton L & b in Skeleton L holds a "\/" b in Skeleton L
  proof
    let L be pseudocomplemented distributive bounded Lattice;
    hereby
      assume
  a0: L is satisfying_Stone_identity;
      let a, b be Element of L;
      assume
X0:   a in Skeleton L & b in Skeleton L; then
      consider x being Element of L such that
X1:   a = x*;
      consider y being Element of L such that
X2:   b = y* by X0;
      (x "/\" y)* in Skeleton L;
      hence a "\/" b in Skeleton L by X1,X2,Th12,a0;
    end;
    assume
a1: for a, b being Element of L st a in Skeleton L & b in Skeleton L
    holds a "\/" b in Skeleton L;
    let y be Element of L;
    y* in Skeleton L & y** in Skeleton L; then
sp: (y* "\/" (y**))** = y* "\/" (y**) by Th13,a1;
r1: y** [= (y* "/\" (y**))* by Th6,LATTICES:6;
    y*** [= (y* "/\" (y**))* by LATTICES:6,Th6; then
    y* [= (y* "/\" (y**))* by Th7; then
r:  (y*) "\/" (y**) [= (y* "/\" (y**))* "\/" ((y* "/\" (y**))*)
      by r1,FILTER_0:4;
s1: (y* "\/" (y**))* [= y** by Th6,LATTICES:5;
    (y* "\/" (y**))* [= y*** by Th6,LATTICES:5; then
s2: (y* "\/" (y**))* [= y* by Th7;
    (y* "\/" (y**))* "/\" ((y* "\/" (y**))*) [= y* "/\" (y**)
      by s1,s2,FILTER_0:5; then
    (y* "/\" (y**))* [= y* "\/" (y**) by sp,Th6;then
    (y* "/\" (y**))* = y* "\/" (y**) by r,LATTICES:8;
    then (Bottom L)* = y* "\/" (y**) by ThD;
    hence thesis by Th11;
  end;

reserve L for Stone Lattice;

:: LTRS: Proposition 45

theorem Lm1:
  Top L in Skeleton L & Bottom L in Skeleton L
proof
  (Top L)* in Skeleton L & (Bottom L)* in Skeleton L;
  hence thesis by Th11a,Th11;
end;

definition let L be Stone Lattice, a be Element of L;
  attr a is skeletal means
    a in Skeleton L;
end;

registration
  let L be Stone Lattice;
  cluster Top L -> skeletal;
  coherence by Lm1;
  cluster Bottom L -> skeletal;
  coherence by Lm1;
end;

:: LTRS: Proposition 45

registration let L be Stone Lattice;
  cluster Skeleton L -> join-closed meet-closed;
  coherence
  proof
    set S = Skeleton L;
tt: for p,q being Element of L st p in S & q in S holds p "\/" q in S
    proof
      let p,q be Element of L;
      assume p in S & q in S; then
      p** = p & q** = q by Th13; then
      p "\/" q = (p* "/\" (q*))* by Th12;
      hence thesis;
    end;
    for p,q being Element of L st p in S & q in S holds p "/\" q in S
    proof
      let p,q be Element of L;
      assume
T1:   p in S & q in S; then
T3:   p = p** by Th13;
      p * [= (p "/\" q)* by Th6,LATTICES:6; then
T2:   (p "/\" q)** [= p** by Th6;
T4:   q = q** by T1,Th13;
      q* [= (p "/\" q)* by Th6,LATTICES:6; then
      (p "/\" q)** [= q** by Th6; then
T5:   (p "/\" q)** [= p "/\" q by T3,T4,T2,FILTER_0:7;
      p "/\" q [= (p "/\" q)** by Th5; then
      p "/\" q = (p "/\" q)** by T5,LATTICES:8;
      hence thesis;
    end;
    hence thesis by tt,LATTICES:def 24,def 25;
  end;
end;

definition let L be Stone Lattice;
  redefine func Skeleton L -> ClosedSubset of L;  :: redefines Skeleton (LATSTONE, definition)
  coherence;
end;

:: Skeleton equipped with the lattice structure

definition let L be Stone Lattice;
  func SkelLatt L -> Sublattice of L equals
  latt (L,Skeleton L);
  coherence;
end;

registration let L be Stone Lattice;
  cluster SkelLatt L -> distributive;
  coherence;
end;

theorem
  Bottom L = Bottom SkelLatt L & Top L = Top SkelLatt L
  proof
    Bottom L in Skeleton L & Top L in Skeleton L by Lm1;
    hence thesis by ThB,ThC;
  end;

LattIsComplemented:
  latt (L,Skeleton L) is complemented
  proof
    set P = Skeleton L;
A0: Bottom L in P & Top L in P by Lm1;
    set LL = latt (L,P);
    for b being Element of LL
    ex a being Element of LL st a is_a_complement_of b
    proof
      let b be Element of LL;
      reconsider bb = b as Element of L by FILTER_2:68;
      set aa = bb*;
      bb* in Skeleton L; then
      reconsider a = aa as Element of LL by FILTER_2:72;
      b in the carrier of LL; then
z1:   b in Skeleton L by FILTER_2:72;
      aa "\/" bb = bb*** "\/" bb by z1,Th13 .= bb*** "\/" (bb**) by z1,Th13
      .= Top L by SatStone; then
A1:   a "\/" b = Top L by FILTER_2:73 .= Top LL by A0,ThC;
      aa "/\" bb = Bottom L by ThD; then
      a "/\" b = Bottom L by FILTER_2:73 .= Bottom LL by A0,ThB;
      hence thesis by LATTICES:def 18,A1;
    end;
    hence thesis by LATTICES:def 19;
  end;

:: LTRS: Proposition 45

registration let L be Stone Lattice;
  cluster SkelLatt L -> Boolean;
  coherence
  proof
    Top L in Skeleton L by Lm1; then
A0: latt (L, Skeleton L) is upper-bounded by ThC;
    Bottom L in Skeleton L by Lm1; then
a2: latt (L, Skeleton L) is lower-bounded by ThB;
    latt (L, Skeleton L) is complemented by LattIsComplemented;
    hence thesis by a2,A0;
  end;
end;

begin :: Dense Elements in Lattices

definition let L be lower-bounded Lattice;
  func DenseElements L -> Subset of L equals
    { a where a is Element of L : a* = Bottom L };
  coherence
  proof
    { a where a is Element of L : a* = Bottom L } c= the carrier of L
    proof
      let x be object;
      assume x in { a where a is Element of L : a* = Bottom L }; then
      consider aa being Element of L such that
A1:   aa = x & aa* = Bottom L;
      thus thesis by A1;
    end;
    hence thesis;
  end;
end;

theorem TopIsDense:
  Top L in DenseElements L
  proof
    (Top L)* = Bottom L by Th11a;
    hence thesis;
  end;

registration let L be Stone Lattice;
  cluster DenseElements L -> non empty;
  coherence by TopIsDense;
end;

definition let L be Stone Lattice, a be Element of L;
  attr a is dense means
    a in DenseElements L;
end;

registration let L be Stone Lattice;
  cluster Top L -> dense;
  coherence by TopIsDense;
end;

theorem DenseIsBot:
  for L being Stone Lattice, x being Element of L st x in DenseElements L holds
    x* = Bottom L
  proof
    let L be Stone Lattice, x be Element of L;
    assume x in DenseElements L; then
    consider aa being Element of L such that
A1: x = aa & aa* = Bottom L;
    thus thesis by A1;
  end;

registration let L be Stone Lattice;
  cluster DenseElements L -> join-closed meet-closed;
  coherence
  proof
A1: for x,y being Element of L st x in DenseElements L & y in DenseElements L
      holds x "\/" y in DenseElements L
    proof
      let x,y be Element of L;
      assume x in DenseElements L & y in DenseElements L; then
A2:   x* = Bottom L & y* = Bottom L by DenseIsBot;
F1:   (x "\/" y)* [= x* by Th6,LATTICES:5;
      Bottom L [= (x "\/" y)* by LATTICES:16; then
      (x "\/" y)* = Bottom L by LATTICES:8,A2,F1;
      hence x "\/" y in DenseElements L;
    end;
    for x,y being Element of L st x in DenseElements L & y in DenseElements L
      holds x "/\" y in DenseElements L
    proof
      let x,y be Element of L;
      assume x in DenseElements L & y in DenseElements L; then
A2:   x* = Bottom L & y* = Bottom L by DenseIsBot;
      (x "/\" y)* = x* "\/" (y*) by Th12;
      hence x "/\" y in DenseElements L by A2;
    end;
    hence thesis by A1,LATTICES:def 25,def 24;
  end;
end;

definition let L be Stone Lattice;
  redefine func DenseElements L -> ClosedSubset of L;  :: redefines DenseElements (LATSTONE, definition)
  coherence;
end;

:: Set of dense elements equipped with the lattice structure

definition let L be Stone Lattice;
  func DenseLatt L -> Sublattice of L equals
    latt (L, DenseElements L);
  coherence;
end;

registration let L be Stone Lattice;
  cluster DenseLatt L -> distributive;
  coherence;
end;

:: Meet-decomposition of elements of a lattice in terms
:: of skeletal and dense elements

theorem
  for L being Stone Lattice, a being Element of L holds
  ex b, c being Element of L st a = b "/\" c & b in Skeleton L &
  c in DenseElements L
  proof
    let L be Stone Lattice, a be Element of L;
A1: a = (a** "/\" a) "\/" Bottom L by LATTICES:4,Th5
     .= (a** "/\" a) "\/" (a** "/\" (a*)) by ThD
     .= a** "/\" (a "\/" (a*)) by LATTICES:def 11;
    take b = a**;
    take c = a "\/" (a*);
G1: (a "\/" (a*))* [= a* by Th6,LATTICES:5;
    (a "\/" (a*))* [= a** by Th6,LATTICES:5; then
    (a "\/" (a*))* [= a* "/\" (a**) by FILTER_0:7,G1; then
    (a "\/" (a*))* [= Bottom L by ThD; then
    (a "\/" (a*))* = Bottom L by BOOLEALG:9;
    hence thesis by A1;
  end;

begin :: An Example: Lattice of Natural Divisors

theorem
  for p being Prime holds NatDivisors p = {1, p}
  proof
    let p be Prime;
a1: NatDivisors (p|^1)={ p|^k where k is Element of NAT:k <= 1 } by NAT_5:19;
    { p|^k where k is Element of NAT : k <= 1 } = {1, p}
    proof
      thus { p|^k where k is Element of NAT : k <= 1 } c= {1, p}
      proof
        let x be object;
        assume x in { p|^k where k is Element of NAT : k <= 1 }; then
        consider kk being Element of NAT such that
A2:     x = p |^ kk & kk <= 1;
        kk = 0 or ... or kk = 1 by A2; then
        x = 1 or x = p |^ 1 by NEWTON:4,A2;
        hence thesis by TARSKI:def 2;
      end;
      let x be object;
      assume x in {1, p}; then
      x = 1 or x = p by TARSKI:def 2; then
      x = p |^ 0 or x = p |^ 1 by NEWTON:4;
      hence thesis;
    end;
    hence thesis by a1;
  end;

theorem DivisorsSquare:
  for p being Prime holds NatDivisors (p * p) = {1, p, p*p}
  proof
    let p be Prime;
a1: NatDivisors (p|^2)={p|^k where k is Element of NAT : k <= 2} by NAT_5:19;
    { p|^k where k is Element of NAT : k <= 2 } = {1, p, p * p}
    proof
      thus { p|^k where k is Element of NAT : k <= 2 } c= {1, p, p * p}
      proof
        let x be object;
        assume x in { p|^k where k is Element of NAT : k <= 2 }; then
        consider kk being Element of NAT such that
A2:     x = p |^ kk & kk <= 2;
        kk = 0 or ... or kk = 2 by A2; then
        x = 1 or x = p or x = p * p by A2,NEWTON:81,4;
        hence thesis by ENUMSET1:def 1;
      end;
      let x be object;
      assume x in {1, p, p * p}; then
      x = 1 or x = p or x = p * p by ENUMSET1:def 1; then
      x = p |^ 0 or x = p |^ 1 or x = p |^ 2 by NEWTON:4,81;
      hence thesis;
    end;
    hence thesis by a1,NEWTON:81;
  end;

registration let n be non zero Nat;
  cluster Divisors_Lattice n -> finite;
  coherence
  proof
    NatDivisors n is finite;
    hence thesis by MOEBIUS2:def 10;
  end;
end;

registration
  cluster complete for Boolean Lattice;
  existence
  proof
    reconsider n = 1 as non zero Nat;
    Divisors_Lattice n is Boolean by MOEBIUS1:22;
    hence thesis;
  end;
end;

registration let p be Prime;
  cluster Divisors_Lattice (p) -> Boolean;
  coherence;
end;

:: Hence it is pseudocomplemented, and Stone

registration let p be Prime;
  cluster Divisors_Lattice (p * p) -> pseudocomplemented;
  coherence
  proof
    set L = Divisors_Lattice (p * p);
    the carrier of Divisors_Lattice (p * p) =
      NatDivisors (p*p) by MOEBIUS2:def 10; then
A1: the carrier of L = {1, p, p * p} by DivisorsSquare;
    for x being Element of L
     ex y being Element of L st y is_a_pseudocomplement_of x
    proof
      let x be Element of L;
      per cases by ENUMSET1:def 1,A1;
      suppose
    C1: x = 1;
        reconsider pp = p * p as Element of L by A1,ENUMSET1:def 1;
        x = Bottom L by C1,MOEBIUS2:64; then
B1:     pp "/\" x = Bottom L;
        for y being Element of L st x "/\" y = Bottom L holds y [= pp
        proof
          let y be Element of L;
          assume x "/\" y = Bottom L;
          pp = Top L by MOEBIUS2:64;
          hence thesis by LATTICES:19;
        end; then
        pp is_a_pseudocomplement_of x by B1;
        hence thesis;
      end;
      suppose
B0:     x = p;
        reconsider pp = Bottom L as Element of L;
        for y being Element of L st x "/\" y = Bottom L holds y [= pp
        proof
          let y be Element of L;
w3:       y = 1 or y = p or y = p * p by A1,ENUMSET1:def 1;
          assume
W1:       x "/\" y = Bottom L;
W2:       y <> Top L
          proof
            assume y = Top L; then
            p = 1 by B0,MOEBIUS2:64,W1;
            hence thesis by INT_2:def 4;
          end;
          y <> p
          proof
            assume y = p; then
            1 = p by W1,MOEBIUS2:64,B0;
            hence thesis by INT_2:def 4;
          end;
          hence thesis by W2,w3,MOEBIUS2:64;
        end; then
        pp is_a_pseudocomplement_of x;
        hence thesis;
      end;
      suppose
    C1: x = p * p;
        reconsider pp = 1 as Element of L by A1,ENUMSET1:def 1;
b1:     pp = Bottom L by MOEBIUS2:64;
        for y being Element of L st x "/\" y = Bottom L holds y [= pp
        proof
          let y be Element of L;
          assume
S1:       x "/\" y = Bottom L;
s3:       y = 1 or y = p * p or y = p by A1,ENUMSET1:def 1;
R2:       Top L = p * p by MOEBIUS2:64;
          y <> p
          proof
            assume y = p; then
            p = 1 by MOEBIUS2:64,S1,R2,C1;
            hence thesis by INT_2:def 4;
          end;
          hence thesis by s3,C1,MOEBIUS2:64,S1;
        end; then
        pp is_a_pseudocomplement_of x by b1;
        hence thesis;
      end;
    end;
    hence thesis;
  end;
end;

theorem PsCompl:
  for L being Lattice, p being Prime, x being Element of L st
    L = Divisors_Lattice (p * p) & x = p holds x* = Bottom L
  proof
    let L be Lattice, p be Prime, x be Element of L;
    assume that
A1: L = Divisors_Lattice (p * p) and
B0: x = p;
    reconsider pp = Bottom L as Element of L;
    for y being Element of L st x "/\" y = Bottom L holds y [= pp
    proof
      let y be Element of L;
      y in the carrier of L; then
      y in NatDivisors (p*p) by A1,MOEBIUS2:def 10; then
      y in {1, p, p*p} by DivisorsSquare; then
w3:   y = 1 or y = p or y = p * p by ENUMSET1:def 1;
      assume
W1:   x "/\" y = Bottom L;
W2:   y <> Top L
      proof
        assume y = Top L; then
        x = 1 by MOEBIUS2:64,A1,W1;
        hence thesis by INT_2:def 4,B0;
      end;
      y <> p
      proof
        assume y = p; then
        1 = p by A1,MOEBIUS2:64,B0,W1;
        hence thesis by INT_2:def 4;
      end;
      hence thesis by W2,w3,A1,MOEBIUS2:64;
    end; then
    pp is_a_pseudocomplement_of x by A1;
    hence thesis by def3,A1;
  end;

:: The example of a lattice which is Stone but not Boolean

registration let p be Prime;
  cluster Divisors_Lattice (p * p) -> satisfying_Stone_identity;
  coherence
  proof
    set L = Divisors_Lattice (p * p);
    let x be Element of L;
    x in the carrier of L; then
    x in NatDivisors (p * p) by MOEBIUS2:def 10; then
    x in {1, p, p * p} by DivisorsSquare; then
    per cases by ENUMSET1:def 1;
    suppose
      x = 1; then
      x = Bottom L by MOEBIUS2:64; then
      x* = Top L by Th11;
      hence thesis;
    end;
    suppose
      x = p; then
      x* = Bottom L by PsCompl;
      hence thesis by Th11;
    end;
    suppose
      x = p * p; then
      x = Top L by MOEBIUS2:64; then
      x* = Bottom L by Th11a;
      hence thesis by Th11;
    end;
  end;
end;

registration let p be Prime;
  cluster Divisors_Lattice (p * p) -> non Boolean Stone;
  coherence
  proof
    p |^ 2 divides (p * p) by NEWTON:81; then
    p * p is square-containing by MOEBIUS1:def 1;
    hence thesis by MOEBIUS2:65;
  end;
end;

registration
  cluster Stone non Boolean for Lattice;
  existence
  proof
    set p = the Prime;
    take Divisors_Lattice (p * p);
    thus thesis;
  end;
end;

:: Every squarefree number generates Stone lattice as it is Boolean

begin :: Products of Pseudocomplemented Lattices

 reserve L1, L2 for Lattice;
 reserve p1, q1 for Element of L1;
 reserve p2, q2 for Element of L2;

theorem ProductPsCompl:
  L1 is 01_Lattice & L2 is 01_Lattice implies
    (p1 is_a_pseudocomplement_of q1 & p2 is_a_pseudocomplement_of q2 iff
      [p1,p2] is_a_pseudocomplement_of [q1,q2])
  proof
    assume
A0: L1 is 01_Lattice & L2 is 01_Lattice;
    set L = [:L1,L2:];
    thus p1 is_a_pseudocomplement_of q1 & p2 is_a_pseudocomplement_of q2
      implies [p1,p2] is_a_pseudocomplement_of [q1,q2]
    proof
      assume
A1:   p1 is_a_pseudocomplement_of q1 & p2 is_a_pseudocomplement_of q2;
      set a = [p1,p2], b = [q1,q2];
a2:   a "/\" b = [Bottom L1, Bottom L2] by A1,FILTER_1:35;
      for x being Element of L st b "/\" x = Bottom L holds x [= a
      proof
        let x be Element of L;
        assume
Z1:     b "/\" x = Bottom L;
        consider x1,x2 being object such that
Z2:     x1 in the carrier of L1 & x2 in the carrier of L2 & x = [x1,x2]
          by ZFMISC_1:def 2;
        reconsider x1 as Element of L1 by Z2;
        reconsider x2 as Element of L2 by Z2;
        [q1,q2] "/\" [x1,x2] = [Bottom L1,Bottom L2] by FILTER_1:42,A0,Z2,Z1;
        then
Z3:     [q1 "/\" x1,q2 "/\" x2] = [Bottom L1,Bottom L2] by FILTER_1:35; then
T1:     q1 "/\" x1 = Bottom L1 by XTUPLE_0:1;
T2:     q2 "/\" x2 = Bottom L2 by Z3,XTUPLE_0:1;
Z4:     x1 [= p1 by T1,A1;
        x2 [= p2 by A1,T2;
        hence thesis by Z2,FILTER_1:36,Z4;
      end;
      hence thesis by a2,FILTER_1:42,A0;
    end;
    assume
W0: [p1,p2] is_a_pseudocomplement_of [q1,q2]; then
    [p1,p2] "/\" [q1,q2] = [Bottom L1,Bottom L2] by A0,FILTER_1:42; then
w1: [p1 "/\" q1, p2 "/\" q2] = [Bottom L1,Bottom L2] by FILTER_1:35; then
W1: p1 "/\" q1 = Bottom L1 & p2 "/\" q2 = Bottom L2 by XTUPLE_0:1;
w2: for xx1 being Element of L1 st q1 "/\" xx1 = Bottom L1 holds xx1 [= p1
    proof
      let xx1 be Element of L1;
      assume q1 "/\" xx1 = Bottom L1; then
      [q1 "/\" xx1, q2 "/\" p2] = Bottom [:L1, L2:]
        by W1,FILTER_1:42,A0; then
      [q1,q2] "/\" [xx1, p2] = Bottom [:L1, L2:] by FILTER_1:35; then
      [xx1,p2] [= [p1,p2] by W0;
      hence thesis by FILTER_1:36;
    end;
    for xx2 being Element of L2 st q2 "/\" xx2 = Bottom L2 holds xx2 [= p2
    proof
      let xx2 be Element of L2;
      assume q2 "/\" xx2 = Bottom L2; then
      [q1 "/\" p1, q2 "/\" xx2] = Bottom [:L1, L2:]
        by W1,FILTER_1:42,A0; then
      [q1,q2] "/\" [p1, xx2] = Bottom [:L1, L2:] by FILTER_1:35; then
      [p1,xx2] [= [p1,p2] by W0;
      hence thesis by FILTER_1:36;
    end;
    hence thesis by w2,w1,XTUPLE_0:1;
  end;

theorem PsComplProduct:
  L1 is 01_Lattice & L2 is 01_Lattice implies (L1 is pseudocomplemented &
  L2 is pseudocomplemented iff [:L1,L2:] is pseudocomplemented)
  proof
    assume
A0: L1 is 01_Lattice & L2 is 01_Lattice;
    thus L1 is pseudocomplemented & L2 is pseudocomplemented implies
    [:L1,L2:] is pseudocomplemented
    proof
      assume
A1:   L1 is pseudocomplemented & L2 is pseudocomplemented;
      for x being Element of [:L1,L2:] holds ex y being Element of [:L1,L2:]
      st y is_a_pseudocomplement_of x
      proof
        let x be Element of [:L1,L2:];
        consider x1, x2 being object such that
B1:     x1 in the carrier of L1 & x2 in the carrier of L2 & x = [x1,x2]
         by ZFMISC_1:def 2;
        reconsider x1 as Element of L1 by B1;
        reconsider x2 as Element of L2 by B1;
        consider xx1 being Element of L1 such that
A2:     xx1 is_a_pseudocomplement_of x1 by A1;
        consider xx2 being Element of L2 such that
A3:     xx2 is_a_pseudocomplement_of x2 by A1;
        take y = [xx1,xx2];
        thus thesis by B1,A2,A3,ProductPsCompl,A0;
      end;
      hence thesis;
    end;
    assume
aa: [:L1,L2:] is pseudocomplemented;
    for x being Element of L1 holds ex y being Element of L1 st
    y is_a_pseudocomplement_of x
    proof
      let x be Element of L1;
      set x2 = the Element of L2;
      consider y being Element of [:L1,L2:] such that
B0:   y is_a_pseudocomplement_of [x,x2] by aa;
      consider y1, y2 being object such that
B1:   y1 in the carrier of L1 & y2 in the carrier of L2 & y = [y1,y2]
        by ZFMISC_1:def 2;
      reconsider y1 as Element of L1 by B1;
      reconsider y2 as Element of L2 by B1;
      take y1;
      thus thesis by B1,B0,ProductPsCompl,A0;
    end;
    hence L1 is pseudocomplemented;
    for x being Element of L2 holds ex y being Element of L2 st
    y is_a_pseudocomplement_of x
    proof
      let x be Element of L2;
      set x2 = the Element of L1;
      consider y being Element of [:L1,L2:] such that
B0:   y is_a_pseudocomplement_of [x2,x] by aa;
      consider y1, y2 being object such that
B1:   y1 in the carrier of L1 & y2 in the carrier of L2 & y = [y1,y2]
        by ZFMISC_1:def 2;
      reconsider y1 as Element of L1 by B1;
      reconsider y2 as Element of L2 by B1;
      take y2;
      thus thesis by B1,B0,ProductPsCompl,A0;
    end;
    hence thesis;
  end;

registration let L1, L2 be pseudocomplemented 01_Lattice;
  cluster [:L1,L2:] -> pseudocomplemented;
  coherence by PsComplProduct;
end;

theorem ProductPCompl:
  L1 is pseudocomplemented 01_Lattice & L2 is pseudocomplemented 01_Lattice
  implies [p1,p2]* = [p1*,p2*]
  proof
    assume
A1: L1 is pseudocomplemented 01_Lattice &
    L2 is pseudocomplemented 01_Lattice;
A3: p1* is_a_pseudocomplement_of p1 by def3,A1;
    p2* is_a_pseudocomplement_of p2 by def3,A1; then
    [p1*,p2*] is_a_pseudocomplement_of [p1,p2] by A3,ProductPsCompl,A1;
    hence thesis by def3,A1;
  end;

 reserve L1, L2 for non empty Lattice;

theorem ProductIsSStone:
  L1 is satisfying_Stone_identity pseudocomplemented 01_Lattice &
  L2 is satisfying_Stone_identity pseudocomplemented 01_Lattice implies
  [:L1,L2:] is satisfying_Stone_identity
  proof
    assume that
A1: L1 is satisfying_Stone_identity pseudocomplemented 01_Lattice and
A2: L2 is satisfying_Stone_identity pseudocomplemented 01_Lattice;
    set L = [:L1,L2:];
    for x being Element of L holds x* "\/" (x**) = Top L
    proof
      let x be Element of L;
      consider x1,x2 being object such that
A3:   x1 in the carrier of L1 & x2 in the carrier of L2 & x = [x1,x2]
        by ZFMISC_1:def 2;
      reconsider x1 as Element of L1 by A3;
      reconsider x2 as Element of L2 by A3;
X1:   [x1*,x2*] = x* by ProductPCompl,A3,A1,A2;
A4:   x1* "\/" (x1**) = Top L1 by A1,SatStone;
      [x1* "\/" (x1**), x2* "\/" (x2**)] = [Top L1, Top L2]
        by A4,A2,SatStone
           .= Top L by FILTER_1:43,A1,A2; then
      Top L = [x1*,x2*] "\/" [x1**,x2**] by FILTER_1:35
           .= x* "\/" (x**) by X1,ProductPCompl,A1,A2;
      hence thesis;
    end;
    hence thesis;
  end;

theorem
  L1 is Stone & L2 is Stone implies [:L1,L2:] is Stone
  by ProductIsSStone,FILTER_1:38;

registration let L1, L2 be Stone Lattice;
  cluster [:L1,L2:] -> Stone;
  coherence by ProductIsSStone,FILTER_1:38;
end;

begin :: Special Construction: B squared

reserve B for Boolean Lattice;

:: LTRS: Lemma 46 - definition

definition let B be Boolean Lattice;
  func B squared -> Subset of [:B,B:] equals
    { [a,b] where a, b is Element of B : a [= b };
  coherence
  proof
    { [a,b] where a, b is Element of B : a [= b } c= the carrier of [:B,B:]
    proof
      let x be object;
      assume x in { [a,b] where a, b is Element of B : a [= b }; then
      consider a1, b1 being Element of B such that
A1:   x = [a1,b1] & a1 [= b1;
      thus thesis by A1;
    end;
    hence thesis;
  end;
end;

registration let B be Boolean Lattice;
  cluster B squared -> non empty;
  coherence
  proof
    set x = Bottom B;
    take [x,x];
    thus thesis;
  end;
end;

registration let B be Boolean Lattice;
  cluster B squared -> join-closed meet-closed;
  coherence
  proof
    set S = B squared;
AA: for p,q being Element of [:B,B:] st p in S & q in S holds p "\/" q in S
    proof
      let p,q be Element of [:B,B:];
      assume
A0:   p in S & q in S; then
      consider a1, b1 being Element of B such that
A1:   p = [a1,b1] & a1 [= b1;
      consider a2, b2 being Element of B such that
A2:   q = [a2,b2] & a2 [= b2 by A0;
A3:   p "\/" q = [a1 "\/" a2, b1 "\/" b2] by FILTER_1:35,A1,A2;
      a1 "\/" a2 [= b1 "\/" b2 by A1,A2,FILTER_0:4;
      hence thesis by A3;
    end;
    for p,q being Element of [:B,B:] st p in S & q in S holds p "/\" q in S
    proof
      let p,q be Element of [:B,B:];
      assume
A0:   p in S & q in S; then
      consider a1, b1 being Element of B such that
A1:   p = [a1,b1] & a1 [= b1;
      consider a2, b2 being Element of B such that
A2:   q = [a2,b2] & a2 [= b2 by A0;
A3:   p "/\" q = [a1 "/\" a2, b1 "/\" b2] by FILTER_1:35,A1,A2;
      a1 "/\" a2 [= b1 "/\" b2 by A1,A2,FILTER_0:5;
      hence thesis by A3;
    end;
    hence thesis by LATTICES:def 24,def 25,AA;
  end;
end;

definition let B be Boolean Lattice;
  redefine func B squared -> non empty ClosedSubset of [:B,B:];  :: redefines squared (LATSTONE, definition)
  coherence;
end;

definition let B be Boolean Lattice;
  func B squared-latt -> Lattice equals
    latt ([:B,B:], B squared);
  coherence;
end;

theorem SquaredCarrier:
  the carrier of (B squared-latt) = B squared
  proof
    set L = [:B,B:];
    set P = B squared;
    consider o1,o2 being BinOp of P such that
A1: o1 = (the L_join of L)||P & o2 = (the L_meet of L)||P &
    latt ([:B,B:], P) = LattStr (#P, o1, o2#) by FILTER_2:def 14;
    thus thesis by A1;
  end;

theorem
  [Bottom B, Bottom B] in the carrier of (B squared-latt)
  proof
    [Bottom B, Bottom B] in B squared;
    hence thesis by SquaredCarrier;
  end;

theorem
  [Top B, Top B] in the carrier of (B squared-latt)
  proof
    [Top B, Top B] in B squared;
    hence thesis by SquaredCarrier;
  end;

registration let B be Boolean Lattice;
  cluster B squared-latt -> lower-bounded;
  coherence
  proof
    Bottom [:B,B:] = [Bottom B, Bottom B] by FILTER_1:42; then
    Bottom [:B,B:] in B squared;
    hence thesis by ThB;
  end;
  cluster B squared-latt -> upper-bounded;
  coherence
  proof
    Top [:B,B:] = [Top B, Top B] by FILTER_1:43; then
    Top [:B,B:] in B squared;
    hence thesis by ThC;
  end;
end;

theorem SquaredBottom:
  Bottom (B squared-latt) = [Bottom B, Bottom B]
  proof
    [Bottom B, Bottom B] in B squared; then
    Bottom [:B,B:] in B squared by FILTER_1:42; then
    Bottom latt ([:B,B:], B squared) = Bottom [:B,B:] by ThB;
    hence thesis by FILTER_1:42;
  end;

theorem SquaredTop:
  Top (B squared-latt) = [Top B, Top B]
  proof
    [Top B, Top B] in B squared; then
    Top [:B,B:] in B squared by FILTER_1:43; then
    Top latt ([:B,B:], B squared) = Top [:B,B:]  by ThC;
    hence thesis by FILTER_1:43;
  end;

registration let B be Boolean Lattice;
  cluster B squared-latt -> pseudocomplemented;
  coherence
  proof
    set L = B squared-latt;
    for x being Element of L holds ex y being Element of L st
      y is_a_pseudocomplement_of x
    proof
      let x be Element of L;
      x in the carrier of L; then
      x in B squared by SquaredCarrier; then
      consider x1,x2 being Element of B such that
A1:   x = [x1,x2] & x1 [= x2;
I1:   [x2`,x2`] in B squared;
      reconsider y = [x2`,x2`] as Element of L by I1,SquaredCarrier;
      take y;
Z1:   x "/\" y = [x1,x2] "/\" [x2`,x2`] by A1,MSUALG_7:11
         .= [x1 "/\" x2`, x2 "/\" x2`] by FILTER_1:35
         .= [x1 "/\" x2`, Bottom B] by LATTICES:20;
      x2` [= x1` by A1,LATTICES:26; then
      x1 "/\" x2` [= x1 "/\" x1` by FILTER_0:5; then
      x1 "/\" x2` [= Bottom B by LATTICES:20; then
tt:   x1 "/\" x2` = Bottom B by BOOLEALG:9;
      for w being Element of L st x "/\" w = Bottom L holds w [= y
      proof
        let w be Element of L;
        assume
O1:     x "/\" w = Bottom L;
        w in the carrier of L; then
        w in B squared by SquaredCarrier; then
        consider w1,w2 being Element of B such that
Y1:     w = [w1,w2] & w1 [= w2;
        [x1,x2] "/\" [w1,w2] = Bottom L by O1,Y1,A1,MSUALG_7:11; then
        [x1,x2] "/\" [w1,w2] = [Bottom B, Bottom B] by SquaredBottom; then
        [x1 "/\" w1,x2 "/\" w2] = [Bottom B, Bottom B] by FILTER_1:35; then
        x1 "/\" w1 = Bottom B & x2 "/\" w2 = Bottom B by XTUPLE_0:1; then
Y2:     w2 [= x2` by LATTICES:25; then
        w1 [= x2` by Y1,LATTICES:7; then
        [w1,w2] "/\" [x2`,x2`] = [w1,w2] by LATTICES:4,Y2,FILTER_1:36; then
        w "/\" y = w by Y1,MSUALG_7:11;
        hence thesis by LATTICES:4;
      end;
      hence thesis by tt,Z1,SquaredBottom;
    end;
    hence thesis;
  end;
end;

theorem PseudoInSquared:
  for L being Lattice, x1,x2 being Element of B, x being Element of L st
    L = B squared-latt & x = [x1,x2] holds x* = [x2`,x2`]
  proof
    let L be Lattice, x1,x2 be Element of B, x be Element of L;
    assume
A0:   L = B squared-latt & x = [x1,x2];
      x in the carrier of L; then
      x in B squared by SquaredCarrier,A0; then
      consider xx1,xx2 being Element of B such that
W1:   x = [xx1,xx2] & xx1 [= xx2;
aa:   xx1 = x1 & xx2 = x2 by W1,A0,XTUPLE_0:1;
      [x2`,x2`] in B squared; then
      reconsider y = [x2`,x2`] as Element of L by A0,SquaredCarrier;
Z1:   x "/\" y = [x1,x2] "/\" [x2`,x2`] by A0,MSUALG_7:11
         .= [x1 "/\" x2`, x2 "/\" x2`] by FILTER_1:35
         .= [x1 "/\" x2`, Bottom B] by LATTICES:20;
      x2` [= x1` by aa,W1,LATTICES:26; then
      x1 "/\" x2` [= x1 "/\" x1` by FILTER_0:5; then
      x1 "/\" x2` [= Bottom B by LATTICES:20; then
tt:   x1 "/\" x2` = Bottom B by BOOLEALG:9;
      for w being Element of L st x "/\" w = Bottom L holds w [= y
      proof
        let w be Element of L;
        assume
O1:     x "/\" w = Bottom L;
        w in the carrier of L; then
        w in B squared by A0,SquaredCarrier; then
        consider w1,w2 being Element of B such that
Y1:     w = [w1,w2] & w1 [= w2;
        [x1,x2] "/\" [w1,w2] = Bottom L by O1,Y1,A0,MSUALG_7:11; then
        [x1,x2] "/\" [w1,w2] = [Bottom B, Bottom B]
          by A0,SquaredBottom; then
        [x1 "/\" w1,x2 "/\" w2] = [Bottom B, Bottom B]
          by FILTER_1:35; then
        x1 "/\" w1 = Bottom B & x2 "/\" w2 = Bottom B by XTUPLE_0:1; then
Y2:     w2 [= x2` by LATTICES:25; then
        w1 [= x2` by Y1,LATTICES:7; then
        [w1,w2] "/\" [x2`,x2`] = [w1,w2] by LATTICES:4,Y2,FILTER_1:36; then
        w "/\" y = w by Y1,MSUALG_7:11,A0;
        hence thesis by LATTICES:4;
      end; then
      y is_a_pseudocomplement_of x by tt,Z1,A0,SquaredBottom;
      hence thesis by def3,A0;
  end;

registration let B be Boolean Lattice;
  cluster B squared-latt -> satisfying_Stone_identity;
  coherence
  proof
    set L = B squared-latt;
    for x being Element of L holds x* "\/" (x**) = Top L
    proof
      let x be Element of L;
      x in the carrier of L; then
      x in B squared by SquaredCarrier; then
      consider x1,x2 being Element of B such that
W1:   x = [x1,x2] & x1 [= x2;
      [x2`,x2`] in B squared; then
      reconsider y = [x2`,x2`] as Element of L by SquaredCarrier;
W0:   x* = [x2`,x2`] by W1,PseudoInSquared; then
      x** = [x2``,x2``] by PseudoInSquared; then
      x* "\/" (x**) = [x2`,x2`] "\/" [x2,x2] by W0,MSUALG_7:11
        .= [x2` "\/" x2, x2` "\/" x2] by FILTER_1:35
        .= [Top B, x2` "\/" x2] by LATTICES:21
        .= [Top B, Top B] by LATTICES:21 .= Top L by SquaredTop;
      hence thesis;
    end;
    hence thesis;
  end;
end;

:: LTRS: Lemma 46, p. 425

registration let B be Boolean Lattice;
  cluster B squared-latt -> Stone;
  coherence;
end;

:: Skeleton and dense elements in the lattice B squared

theorem
  Skeleton (B squared-latt) = the set of all [a,a] where a is Element of B
  proof
    set L = B squared-latt;
    Skeleton (B squared-latt) = the set of all [a,a] where a is Element of B
    proof
      thus Skeleton (B squared-latt)
      c= the set of all [a,a] where a is Element of B
      proof
        let x be object;
        assume x in Skeleton L; then
        consider a being Element of L such that
A1:     x = a*;
        a in the carrier of L; then
        a in B squared by SquaredCarrier; then
        consider a1,a2 being Element of B such that
A2:     a = [a1,a2] & a1 [= a2;
        a* = [a2`,a2`] by A2,PseudoInSquared;
        hence thesis by A1;
      end;
      let x be object;
      assume x in the set of all [a,a] where a is Element of B; then
      consider a being Element of B such that
B1:   x = [a,a];
      set b = [a`,a`];
      b in B squared; then
      reconsider b as Element of L by FILTER_2:72;
      reconsider a1 = b* as Element of L;
      b* = [a``,a``] by PseudoInSquared .= [a,a];
      hence thesis by B1;
    end;
    hence thesis;
  end;

theorem
  DenseElements (B squared-latt) = the set of all [a,Top B]
    where a is Element of B
  proof
    set L = B squared-latt;
    thus DenseElements L c= the set of all [a,Top B] where a is Element of B
    proof
      let x be object;
      assume x in DenseElements L; then
      consider a being Element of L such that
A1:   x = a & a* = Bottom L;
      x in the carrier of L by A1; then
      x in B squared by SquaredCarrier; then
      consider a1, a2 being Element of B such that
A2:   x = [a1,a2] & a1 [= a2;
A3:   a* = [Bottom B, Bottom B] by A1,SquaredBottom;
      a* = [a2`,a2`] by A1,A2,PseudoInSquared; then
      a2`` = (Bottom B)` by A3,XTUPLE_0:1; then
      a2 = Top B by LATTICE4:30;
      hence thesis by A2;
    end;
    let x be object;
    assume x in the set of all [a,Top B] where a is Element of B; then
    consider a being Element of B such that
A1: x = [a, Top B];
    a [= Top B by LATTICES:19; then
    x in B squared by A1; then
    reconsider y = x as Element of L by SquaredCarrier;
    y* = [(Top B)`,(Top B)`] by A1,PseudoInSquared; then
    y* = [Bottom B, (Top B)`] by LATTICE4:29
     .= [Bottom B, Bottom B] by LATTICE4:29
     .= Bottom L by SquaredBottom;
    hence thesis;
  end;